# Line slope calculator 5x+3y=50

**Straight line given by points A[4; 10] and B[7; 5]**

## Calculation:

**Slope-intercept form of line:**y = -1.6667x+16.6667

**Canonical form of the line equation:**5x+3y-50 = 0

**Parametric form of the line equation:**

x = 3t+4

y = -5t+10 ; t ∈ R

**Slope:**m = -1.6667

**Slope angle of line: φ =**-59°2'10″ = -1.0304 rad

**X intercept:**x

_{0}= 10

**Y intercept:**y

_{0}= q = 16.6667

**Distance line from the origin:**d

_{0}= 8.5749

**The length of the segment AB: |AB| =**5.831

**Vector: AB =**(3; -5)

**Normal vector: n =**(5; 3)

**Midpoint of the segment AB: M =**[5.5; 7.5]

**Perpendicular Bisector equation:**3x-5y+21 = 0

**Vector OA = (4; 10) ; |OA| = 10.7703**

**Vector OB = (7; 5) ; |OB| = 8.6023**

**Scalar product OA .OB = 78**

**Angle ∠ AOB = 32°39'39″ = 0.57 rad**