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The ideas in this lesson are taken from Multiplication Division 3 ebook. Only a few examples of each problem type are shown; you should make more problems of each kind for the student. Divisibility rules
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| Numbers that are
divisible by 2 end in __, __, __, __, or __.
Numbers that are divisible by 5 end in either __ or __. Numbers that are divisible by 10 end in __ . |
Division rule for 3 is different. No longer do we check in what the
number ends:
In other words, we add the digits of the number, and if that is divisible
by 3, so is the original number.
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1. Check if these numbers are divisible by three. Then divide the number by 3 in your notebook and record the answer here. What is the remainder if the number IS divisible by 3?
| Number | sum of its digits |
divisible by 3 |
division result |
| 771
8096 2304 |
771 ÷
3 = ___, R ___
8096 ÷ 3 = ___, R ___ 2304 ÷ 3 = ___, R ___ |
Division rule for 9 is similar to the division rule for 3.
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2. Check if these numbers are divisible by nine. Then divide the number by 9 in your notebook and record the answer here. What is the remainder if the number IS divisible by 9?
| Number | sum of its digits |
divisible by 9 |
division result |
| 771
1000 333 |
771 ÷
9 = ___, R ___
1000 ÷ 9 = ___, R ___ 333 ÷ 9 = ___, R ___ |
3. Use the divisibility rules and check if the number is divisible by 2, 3, 5, or 9.
| divisible by | divisible by | |||||||||
| Number | 2 | 3 | 5 | 9 | Number | 2 | 3 | 5 | 9 | |
| 238
6095 |
477
5770 |
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Division rule for 6 says
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4. Check if these numbers are divisible by six. If it is, then divide the number by 6 in your notebook and record the answer here.
| Number |
divisible by 6 |
division result |
| 771
8196 1000 |
771 ÷
6 = ___, R ___
8196 ÷ 6 = ___, R ___ 1000 ÷ 6 = ___, R ___ |
5. a) Find two numbers that are divisible by both 10 and 3.
b) Find two numbers that are divisible by both 2 and 9.
continue to factoring
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